?unsigned char d[10];??? //用于顯示的10位顯示緩存

?//========================================================
???? //16進(jìn)制to10進(jìn)制輸出子程序:顯示數(shù)據(jù)，起始位，結(jié)束位，有無小數(shù)點(diǎn)
?//========================================================
?void output(unsigned long dd,unsigned char s,unsigned char
?e,unsigned char dip) {
???? unsigned long div;
???? unsigned char tm[8],i,j;
???? div=10000000;
???? for (i=0;i<8;i++) {
???????? tm[i]=dd/div;
???????? dd%=div;
???????? div/=10;
???? }
???? for (i=0;i<6;i++) {
???????? if (tm[i]!=0) break;
???????? tm[i]=nul;
???? }
???? tm[5]|=dip;??????????? //小數(shù)點(diǎn)控制，請(qǐng)看“串行LED數(shù)碼管顯示驅(qū)動(dòng)程序”
???? j=7;
???? for (i=s;i???????? d[i]=tm[j];
???????? j--;
???? }
?}

?//把顯示位5-9位的10進(jìn)制數(shù)轉(zhuǎn)換成為16進(jìn)制數(shù)
?unsigned int input(void) {
???? unsigned int dd,dat;
???? dd=10000;dat=0;
???? for (i=5;i<10;i++) {
???????? dat+=dd*temp;
???????? dd/=10;
???? }
???? return(dat);
?}
?/*??? 89C51系列CPU編程器接收CPU程序*/

?＃i nclude
?＃i nclude
?＃i nclude

?#define e 8
?#define p 9
?#define l 10

?sbit led=P3^2;
?sbit p27=P2^7;
?sbit p26=P2^6;
?sbit p36=P3^6;
?sbit p37=P3^7;
?sbit rst=P3^3;
?sbit ale=P3^5;
?sbit vpp=P3^4;

?bit b_break;
?unsigned int adds;

?//??? 13.8mS
?void int_t0(void) interrupt 1 {
???? TH0=-100;
???? b_break=1;
?}

?void wait(unsigned char w) {
???? unsigned int t=w*184;
???? b_break=0;
???? TL0=-t%256-1;TH0=-t/256;
???? while (b_break==0) {}
?}

?void nop(void) {
???? _nop_();_nop_();_nop_();_nop_();
???? _nop_();_nop_();_nop_();_nop_();
???? _nop_();_nop_();_nop_();_nop_();
???? _nop_();_nop_();_nop_();_nop_();
???? _nop_();_nop_();_nop_();_nop_();
?}

?unsigned char command(void) {
???? TH0=-100;b_break=0;
???? while (RI==0) {if (b_break==1) return(0);}
???? RI=0;
???? return(SBUF);
?}

?void earsure(unsigned char cpu) {
???? switch (cpu) {
???? case 1:??????? //89C51
???? case 2:rst=p26=1;p27=p36=p37=0;nop();vpp=1;nop();
???????? ale=0;wait(110);ale=1;nop();
???????? break;
???? case 3:
???? case 4:break;
???? case 5:
???? case 6:break;
???? }
?}

?void program(unsigned char cpu) {
???? unsigned int bdata adds=0;
???? unsigned char d;
???? switch (cpu) {
???? case 1:??? //89C51
???? case 2:
???????? p36=p37=1;rst=1;
???????? while (1) {
???????????? TH0=-100;b_break=0;
???????????? while (RI==0) {if (b_break==1) return;}
???????????? RI=0;
???????????? d=SBUF;
???????????? //address
???????????? P0=adds%256;
???????????? P2=adds/256;
???????????? p27=1;
???????????? //data
???????????? P1=d;
???????????? nop();??? //48clcl
???????????? //vpp
???????????? vpp=1;
???????????? nop();??? //48clcl
???????????? //ale
???????????? ale=0;
???????????? wait(1);//100uS
???????????? ale=1;
???????????? nop();??? //10uS
???????????? vpp=0;
???????????? nop();??? //48clcl
???????????? p27=0;
???????????? nop();??? //48clcl
???????????? P1=0xff;
???????????? TH0=-100;b_break=0;
???????????? while (d!=P1) {if (b_break==1) return;}??? //data
polling
???????????? SBUF=d;
???????????? adds++;
???????? }
???????? break;
???? case 3:
???? case 4:
???? case 5:
???? case 6:break;
???? }
?}

?void lock(unsigned char cpu) {
???? unsigned char i;
???? switch (cpu) {
???? case 1:??? //89c51
???? case 2:
???????? //lock 1
???????? rst=p26=p36=p27=p37=1;nop();
???????? vpp=1;
???????? nop();
???????? ale=0;
???? //??? for (i=0;i<6;i++) wait(100);
???????? wait(1);
???????? ale=1;
???????? nop();
???????? vpp=0;
???????? nop();
????
???????? //lock 2
???????? rst=p26=p27=1;p36=p37=0;nop();
???????? vpp=1;
???????? nop();
???????? ale=0;
???? //??? for (i=0;i<6;i++) wait(100);
???????? wait(1);
???????? ale=1;
???????? nop();
???????? vpp=0;
???????? nop();
????????
???????? //lock 3
???????? rst=p26=p36=1;p27=p37=0;nop();
???????? vpp=1;
???????? nop();
???????? ale=0;
???? //??? for (i=0;i<6;i++) wait(100);
???????? wait(1);
???????? ale=1;
???????? nop();
???????? vpp=0;
???????? nop();
???????? break;
???? case 3:
???? case 4:
???? case 5:
???? case 6:break;
???? }
?}

?void main(void) {
???? unsigned char disp,flash,temp,cpu;
???? EA=1;
???? SCON=0xd8;PCON=0x80;
???? TMOD=0x21;
???? TL1=TH1=0xff;TR1=1;
???? TH0=-100;ET0=TR0=1;

???? flash=0x80;

???? while (1) {
???????? temp=command();
???????? switch (temp) {
???????? case 0:
???????? case 1:??????? //89c51
???????? case 2:??????? //89C52
???????? case 3:??????? //80f51
???????? case 4:??????? //80F52
???????? case 5:??????? //87F51
???????? case 6:cpu=temp;SBUF=temp;break;//87f52
???????? case e:SBUF=temp;earsure(cpu);break;??? //erasure
???????? case p:SBUF=temp;program(cpu);break;??? //program
???????? case l:lock(cpu);SBUF=temp;break;??? //lock
???????? default:SBUF=temp;break;
???????? }
???????? b_break=0;
???????? if ((++disp)>flash) {disp=0;led=!led;}
???? }
?}
?//HT1380實(shí)時(shí)時(shí)鐘驅(qū)動(dòng)程序

?sbit clock_dat=P0^1;
?sbit clock_clk=P0^2;
?sbit clock_rst=P0^3;

?sbit a0=ACC^0;
?sbit a1=ACC^1;
?sbit a2=ACC^2;
?sbit a3=ACC^3;
?sbit a4=ACC^4;
?sbit a5=ACC^5;
?sbit a6=ACC^6;
?sbit a7=ACC^7;

?void clock_out(unsigned char dd) {
???? ACC=dd;
???? clock_dat=a0;clock_clk=1;clock_clk=0;
???? clock_dat=a1;clock_clk=1;clock_clk=0;
???? clock_dat=a2;clock_clk=1;clock_clk=0;
???? clock_dat=a3;clock_clk=1;clock_clk=0;
???? clock_dat=a4;clock_clk=1;clock_clk=0;
???? clock_dat=a5;clock_clk=1;clock_clk=0;
???? clock_dat=a6;clock_clk=1;clock_clk=0;
???? clock_dat=a7;clock_clk=1;clock_clk=0;
?}
?unsigned char clock_in(void) {
???? clock_dat=1;
???? a0=clock_dat;
???? clock_clk=1;clock_clk=0;a1=clock_dat;
???? clock_clk=1;clock_clk=0;a2=clock_dat;
???? clock_clk=1;clock_clk=0;a3=clock_dat;
???? clock_clk=1;clock_clk=0;a4=clock_dat;
???? clock_clk=1;clock_clk=0;a5=clock_dat;
???? clock_clk=1;clock_clk=0;a6=clock_dat;
???? clock_clk=1;clock_clk=0;a7=clock_dat;
???? return(ACC);
?}
?unsigned char read_clock(unsigned char ord) {
???? unsigned char dd=0;
???? clock_clk=0;
???? clock_rst=0;
???? clock_rst=1;
???? clock_out(ord);
???? dd=clock_in();
???? clock_rst=0;
???? clock_clk=1;
???? return(dd);
?}
?void write_clock(unsigned char ord,unsigned char dd) {
???? clock_clk=0;
???? clock_rst=0;
???? clock_rst=1;
???? clock_out(ord);
???? clock_out(dd);
???? clock_rst=0;
???? clock_clk=1;
?}
?/*單個(gè)漢字庫(kù)字摸提取程序，tc2.0編譯*/
?＃i nclude "stdio.h"
?＃i nclude "dos.h"
?＃i nclude "process.h"
?＃i nclude "string.h"

?void main(void) {
???? long int num_bytes,qm,wm;
???? unsigned char d,i,j,k,a[132],b[132];
???? unsigned char * data;
???? unsigned char * hz;
???? static unsigned? char dd[103];
???? FILE *fp;

???? if ((fp=fopen("hzk16f","rb"))==NULL) {
???????? printf("can't open hzk16\n");
???????? exit(1);
???? }
???? clrscr();
???? while (1) {

???????? data=(unsigned char *) malloc(33);
???????? printf("please input:\n");
???????? scanf("%s",dd);??? /*輸入一個(gè)漢字*/

???????? qm=* dd;??????? /*通過區(qū)位碼計(jì)算其在hzk16f文件中的偏移地址*/
???????? qm=qm-161;
???????? if (qm>87) exit(0);
???????? wm=* (dd+1);
???????? wm=wm-161;
???????? if (wm>94) exit(0);
???????? num_bytes=((long)qm*94+wm)*32;
???????? fseek(fp,num_bytes,SEEK_SET);
???????? fgets(data,33,fp);
???????? for (i=0;i<32;i++) b[i]=* data++;
???????? for (i=0;i<32;i+=2) a[i/2]=b[i];
???????? for (i=0;i<32;i+=2) a[i/2+16]=b[i+1];
???????? for (i=8;i<16;i++) b[i]=a[i];
???????? for (i=8;i<16;i++) a[i]=a[i+8];
???????? for (i=8;i<16;i++) a[i+8]=b[i];

???????? /*轉(zhuǎn)換，hzf16f在電腦的儲(chǔ)存格式是以行為字節(jié)計(jì)算的，一般的lcd都采用以列為字節(jié)計(jì)算*/
???????? for (k=0;k<32;k+=8) {
???????????? for (j=0;j<8;j++) {
???????????????? d=0;
???????????????? for (i=0;i<8;i++) {
???????????????????? if (a[i+k]>=0x80) {
???????????????????????? switch (i) {
???????????????????????? case 0:d+=1;break;
???????????????????????? case 1:d+=2;break;
???????????????????????? case 2:d+=4;break;
???????????????????????? case 3:d+=8;break;
???????????????????????? case 4:d+=0x10;break;
???????????????????????? case 5:d+=0x20;break;
???????????????????????? case 6:d+=0x40;break;
???????????????????????? case 7:d+=0x80;break;
???????????????????????? }
???????????????????? }
???????????????? }
???????????????? for (i=0;i<8;i++) a[i+k]<<=1;
???????????????? b[j+k]=d;
???????????? }
???????? }
???????? clrscr();
???????? printf("/*%s:*/\n",dd);??????? /*輸出0x00格式的16進(jìn)制數(shù)*/
???????? for (k=0;k<32;k+=8) {
???????????? for (j=0;j<8;j++) printf("0x%x,",b[j+k]);
???????????? printf("\n");
???????? }
???????? getch();
???? }
?}
?//按鍵掃描驅(qū)動(dòng)程序

?unsigned char key,key_h,kpush;
?unsigned int key_l;

?//按鍵連接到p1.0、p1.1、p1.2

?void int_t0(void) interrupt 1 {
???? unsigned char dd,i;
???? TL0=TL0+30;TH0=0xfb;??? //800
???? /*??? 按鍵判別??? */
???? if ((P1&0x7)==0x7) {
???????? if ((key_l>30)&&(key_l<800)&&(key_h>30)) {???????
?//釋放按鍵，如果之前按鍵時(shí)間少于1秒，讀入鍵值
???????????? key=kpush;
???????? }
???????? if ((++key_h)>200) key_h=200;
???????? key_l=0;
???????? if (key>=0x80) key=0;???????????????????????????
?//如果之前的按鍵為長(zhǎng)按1秒，清除鍵值
???? } else {
???????? kpush=P1&0x7;
???????? key_l++;
???????? if ((key_l>800)&&(key_h>30)) {???????????????????
?//如果按鍵超過1秒，鍵值加0x80標(biāo)志長(zhǎng)按鍵
???????????? key=kpush|0x80;
???????????? key_h=0;
???????????? key_l=0;
???????? }
???? }
?}
?void main(void) {
???? TMOD=0x1;TR0=1;ET0=1;EA=1;
???? while (1) {
???????? while (!key) {}
???????? switch (key) {
???????? case 1:break;
???????? case 2:break;
???????? }
???? }
?//串行驅(qū)動(dòng)led顯示，
?//一個(gè)74hc595位移寄存器驅(qū)動(dòng)三極管驅(qū)動(dòng)led位，
?//兩個(gè)74hc595驅(qū)動(dòng)led段，方式位5位x8段x2=10個(gè)數(shù)碼管
?//5分頻，每次掃描時(shí)間位1.25ms

?//定義特殊符號(hào)

?#define nul 0xf
?#define qc 0xc
?#define qb 0xb
?#define q_ 0xa
?#define q__ 0xd
?#define q___ 0xe
?#define qp 0x10
?#define qe 0x11
?#define qj 0x12
?#define qn 0x13
?#define qf 0x14
?#define qa 0x15
?#define qr 0x16
?#define qd 0x17
?#define qu 0x18
?#define ql 0x19
?#define qh 0x1a
?#define qwen 0x1b
?#define qt 0x1c
?#define qla 0x1d
?#define qlb 0x1e
?#define qlc 0x1f
?#define qld 0x20
?#define qle 0x21
?#define qlf 0x22
?#define qlg 0x23
?#define qldp 0x24

?//顯示段信息，不同led排列組合的段信息只需更改8個(gè)數(shù)值即可。
?//因此，該定義具有通用性。

?//??? 顯示???
?//??????? -d 20
?//??? |c 40??? |e 10
?//??????? - g??????? 80???????
?//??? |b 2??? |f 4
?//??????? _a1??? .dp 8
?#define pa 1
?#define pb 2
?#define pc 0x40
?#define pd 0x20
?#define pe 0x10
?#define pf 4
?#define pg 0x80
?#define pdp 8

?//--------------
?#define l0 pdp+pg
?#define l1 255-pf-pe
?#define l2 pdp+pc+pf
?#define l3 pdp+pc+pb
?#define l4 pdp+pa+pb+pd
?#define l5 pdp+pb+pe
?#define l6 pdp+pe
?#define l7 pdp+pc+pg+pb+pa
?#define l8 pdp
?#define l9 pdp+pb
?#define la pdp+pa
?#define lb pdp+pd+pe
?#define lc pdp+pg+pe+pf
?#define ld pdp+pc+pd
?#define le pdp+pe+pf
?#define lf pdp+pe+pf+pa
?#define l_ 255-pg
?#define lnul 255
?#define ll pdp+pg+pd+pf+pe
?#define lp pdp+pa+pf
?#define lt pdp+pd+pe+pf
?#define lr pdp+pe+pf+pg+pa
?#define ln pdp+pg+pa
?#define lh pdp+pd+pe+pa
?#define ly pdp+pb+pd
?#define lu pdp+pg+pd
?#define l__ pdp+pg+pb+pc+pe+pf
?#define l___ l__-pg
?#define l_1 255-pa
?#define l_2 255-pa-pg
?#define lj 255-(pe+pf+pa)
?#define lwen 255-(pd+pe+pg+pb)
?#define lall 0

?#define lla 255-pa
?#define llb 255-pb
?#define llc 255-pc
?#define lld 255-pd
?#define lle 255-pe
?#define llf 255-pf
?#define llg 255-pg
?#define lldp 255-pdp

?//串行送出的位信息，目前是10位led顯示。
?unsigned char code un_dig[]={0x7f,0xbf,0xdf,0xef,0xf7,0xfb};
?//串行送出的短信息。
?unsigned char code
?un_disp[]={l0,l1,l2,l3,l4,l5,l6,l7,l8,l9,l_,lb,lc,l__,l___,lnul,lp,le,lj,ln,lf,la,lr,ld,lu,
?ll,lh,lwen,lt,lla,llb,llc,lld,lle,llf,llg,lldp,lnul};

?sbit d_clk=P0^0;??????? //移位時(shí)鐘
?sbit d_dat=P0^1;??????? //移位數(shù)據(jù)
?sbit d_st=P0^2;??????????? //移位鎖定

?unsigned char dig;??????????? //位掃描計(jì)數(shù)器
?unsigned char d[10];??????????????????????????? //顯示緩沖

?//送出8位串行數(shù)據(jù)
?void out_disp(unsigned char dd) {
???? unsigned char i;
???? for (i=0;i<8;i++) {
???????? if (dd&1) d_dat=1; else d_dat=0;
???????? d_clk=0;
???????? dd>>=1;
???????? d_clk=1;
???? }
?}
?//控制小數(shù)點(diǎn)和閃爍，顯示數(shù)據(jù)|0x040表示有小數(shù)點(diǎn)；顯示數(shù)據(jù)|0x80表示閃爍。
?void out_displ(unsigned char dd) {
???? if (dd>=0x80) {
???????? if (s001>flash_time) {out_disp(0xff);return;}
???? }
???? dd&=0x7f;
???? if (dd>=0x40) {
???????? dd=un_disp[dd&0x3f]^pdp;
???? } else dd=un_disp[dd];
???? out_disp(dd);
?}